Question: The equation 6u5 ln u + 3v In v = 2w In w defines w as a differentiable function of u and u in

The equation 6u5 ln u + 3v In v = 2w In 

The equation 6u5 ln u + 3v In v = 2w In w defines w as a differentiable function of u and u in the neighborhood of the point (uo, vo, wo) = (1, 1, 1), i.e., w = w(u, v). Find: The first-order partial derivative w(1, 1) = 3 The second-order partial derivative w(1, 1) = The second-order partial derivative wi2 (1, 1) -3 -3 x. X

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