The equation below gives the closed-loop transfer function of a system, with R(s)-1//s and, so I(S)-(Y(s))...

  

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The equation below gives the closed-loop transfer function of a system, with R(s)-1//s and, so I(S)-(Y(s)) (R(s))=(s+4)/((s^(2)+7s+10)(s+5))quad" and "Y(s)= (s+4)/(s(s^(2)+7s+10)(-5)) Factorize the characteristic equation into its simple components, and (a) Resolve the equation above into its partial fractions. (Hint: Consider repeated roots). (b) Determine the unit step response for the system (y(t)= ?) SOLUTIONS: a) Resolve the equation above into its partial fractions. b) Determine the unit step response for the system (y(t)= ?) The equation below gives the closed-loop transfer function of a system, with R(s)-1//s and, so I(S)-(Y(s)) (R(s))=(s+4)/((s^(2)+7s+10)(s+5))quad" and "Y(s)= (s+4)/(s(s^(2)+7s+10)(-5)) Factorize the characteristic equation into its simple components, and (a) Resolve the equation above into its partial fractions. (Hint: Consider repeated roots). (b) Determine the unit step response for the system (y(t)= ?) SOLUTIONS: a) Resolve the equation above into its partial fractions. b) Determine the unit step response for the system (y(t)= ?)