The equation defines a one$-to-$one function $f.$

$f(x)=5x-8$

Determine $f^{-1}(x).$

$f^{-1}(x)=$

Verify that $(f$@$f^{-1})(x)$ and $(f^{-1}$@$f)(x)$ are both the identity function.

$(f$@$f^{-1})(x)=f(f^{-1}(x))$

$=f(1)-8$

$=5(1)+8$

$=-8$

$=x,$