The equation defines a one$-to-$one function $f.$

$f(x)=\frac{1}{x-5}$

Determine $(f^{-1})(x).$

$(f^{-1})(x)=$

Verify that $(f$@$f^{-1})(x)$ and $(f^{-1}$@$f)(x)$ are both the identity function.