The expression $\frac{3}{4}ln(9+\frac{3}{4})+\frac{3}{4}ln(9+\frac{3}{2})+\frac{3}{4}ln(9+\frac{9}{4})+\frac{3}{4}ln(9+3)$ is a Riemann sum approximation of which of the following integrals?

Your answer:

${\displaystyle \underset{4}{\overset{7}{}}}ln(5+\frac{x}{4})dx$

$\frac{1}{4}{\displaystyle \underset{0}{\overset{4}{}}}ln(5+x)dx$

$\frac{1}{4}{\displaystyle \underset{4}{\overset{7}{}}}ln(5+x)dx$

${\displaystyle \underset{4}{\overset{7}{}}}ln(5+x)dx$

${\displaystyle \underset{0}{\overset{4}{}}}ln(4+x)dx$