The expression $(x*y+z)*(x*y+w)$ is equal to

A$)(x+z)(y+w)$

B$)x*z+y*w$

C$)x*y+z*w$

D$)(y+z)(x+w)$

E$)$ none of the above.

$25.$

Using Boolean algebra, the function $F=xy{z}^{\text{'}}+xyz+zy+x{y}^{\text{'}}z+x{y}^{\text{'}}{z}^{\text{'}}+z{y}^{\text{'}}$ can be simplified to

A$)x*z$

B$)x*y^{\text{'}}*z^{\text{'}}$

C$)x+z$

D$)x*y+y^{\text{'}}z$

E$)$ none of the above.

$26.$

Using Boolean algebra, find $F$ if its inverse $F^{\text{'}}=(x^{\text{'}}+y)x+(x^{\text{'}}+y)y^{\text{'}}+z{z}^{\text{'}}$

A$)F=x{y}^{\text{'}}+xy$

B$)F=x^{\text{'}}y+x{y}^{\text{'}}$

C$)F=xy+x^{\text{'}}$

D$)F=x+y+z$

E$)$ none of the above.

$27.$

The canonical form of the boolean function $f(x,y,z)=(x+y)*(x+z)$ is equal to

A$)$ prodM$(6,5)$

B$)$ prodM$(0,1,2)$

C$)$ prodM$(0,1)$

D$)$ prodM$(5,6,7)$

E$)$ none of the above.

$8/10$