Question: The first step from the above solution uses KCL to find out Va. By KCL: 2A=I1+I2 I1=V/R=Va/4 For I2=(Va-4)/4, why Va need to -4 and

Example 2-23: (circuit with voltage source): Solve for V, and I .

The first step from the above solution uses KCL to find out Va.

By KCL: 2A=I1+I2

I1=V/R=Va/4

For I2=(Va-4)/4, why Va need to -4 and where does it come from?

Example 2-23: (circuit with voltage source): Solve for V, and I . Va I2 2 A(t 4 2 +. 4 V Soln.: Write KCL equation at V.. V. V.-4 2 = a + 4 @Va: %3D 4 2V, - 4 = 8 a Ans.: V, = 6V, I, = 1.5V %3D %3D a

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