Question: the foldr I use is fun foldr f e nil = e | foldr f e (a::b) = f a (foldr f e b); but

the foldr I use is
fun foldr f e nil = e
| foldr f e (a::b) = f a (foldr f e b);
but I don't understand how that function turning into partition
 the foldr I use is fun foldr f e nil =

2. Revisit the previous question, but this time, you cannot define the partition from first principles (as a recursive function) nor can you use the List partition basis function. The only thing you can use is the higher-order function foldr. fun qHigh I 2. Revisit the previous question, but this time, you cannot define the partition from first principles (as a recursive function) nor can you use the List partition basis function. The only thing you can use is the higher-order function foldr. fun qHigh

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