the following $3$ equations can be represented by matrix A and vector b$.$

a$.$ b$.$

$2\mathrm{.}5$x$1+3$x$21\mathrm{.}2$x$3=0\mathrm{.}255\mathrm{.}2$x$15\mathrm{.}2$x$2+6\mathrm{.}5$x$3=26\mathrm{.}7$x$10\mathrm{.}5$x$2+0\mathrm{.}75$x$3=4$

Use the command rref$()$to place the augmented matrix in reduced row echelon form to solve for x$.$ Store the final results of x$1$ x$2$ x$3$ in an array $($or vector$)$ called $$x$.-1$

Another way to solve the above system is to apply the following formula, where A is the inverse matrix of A

A$1$ Ax $=$ A$1$b

Use the above relationship to solve for x$.$ Remember the product of A$-1$A gives you the identity matrix. The answers that you obtained in b$)$ should be same as the answers in a$).$