The following algorithm computes the product of two non-negative integers x and y 1. Precondition:...

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The following algorithm computes the product of two non-negative integers x and y 1. \\ Precondition: x >=y >=0 2. int Mult (int x, int y) { 3. 4. 5. 6. 7. 8. 9. 10. 11. 12.) int R=0; int a-x, b=y; while (b>0){ } if (b% 2 == 1) R+= a; a<<=1; b>>=1; return R; a) Give the exact number of bit shifts executed (lines 8 and 9) as a function of y. Justify. b) Give the time complexity of this algorithm using the big-Oh notation. Give the simplest possible expression inside your big-Oh. The following algorithm computes the product of two non-negative integers x and y 1. \\ Precondition: x >=y >=0 2. int Mult (int x, int y) { 3. 4. 5. 6. 7. 8. 9. 10. 11. 12.) int R=0; int a-x, b=y; while (b>0){ } if (b% 2 == 1) R+= a; a<<=1; b>>=1; return R; a) Give the exact number of bit shifts executed (lines 8 and 9) as a function of y. Justify. b) Give the time complexity of this algorithm using the big-Oh notation. Give the simplest possible expression inside your big-Oh.