The following data are from a completely randomized design. Treatment Treatment Treatment A B C 32 46 32 30 45 35 30 46 34 26 48 35 32 50 39 Sample mean 30 47 35 Sample variance 5.0 4,00 6.50 a. At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment 343.3 Sum of Squares, Error 66.0 0 Mean Squares, Treatment 371.7* Mean Squares, Error 5.5 0 Calculate the value of the test statistic (to 2 decimals). The p-value is less than 0.01 What is your conclusion? Conclude that not all treatment means are equal V V b. Calculate the value of Fisher's LSD (to 2 decimals). x Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05. Difference Absolute Value Conclusion 17.00 Significant difference X Significant difference X Significant difference c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers. -20.23 , -13.77