The following data are from a completely randomized design. Treatment A B C 163 142 127 141 157 123 166 125 139 146 141 140 147 135 149 167 146 120 Sample mean 155 141 133 Sample 134.0 variance 114.8 129.2 (a) Compute the sum of squares between treatments. (b) Compute the mean square between treatments. (c) Compute the sum of squares due to error. (d) Compute the mean square due to error. (Round your answer to two decimal places.) (e) Set up the ANOVA table for this problem. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum Degrees Mean of Variation of Squares of Freedom Square F p-value Treatments Error Total{f] At the a = CLUE level of siqnificancer test whether the means for the three treatments are equal. State the null and alternative hvpotheses. '1'.\"- Ho: Not all the population means are equal. Ha: #15. = l\"s = l\"c C\"- HD: \"A e #3 at I\": Ha: #A = #s = #c ('3 Ho: \"A: its=#c Ha: Not all the population means are equal. LI? Ho: At least two of the population means are equal. H3: at least two ofthe population means are different. '3 Ho: \"A = \"a = \"c Ha: luA of pa: \"(3 Find the value of the test statistic. {Round vour answer to two decimal places.) : Find the pvalue. [Round vour answer to four decimal places.) State vour conclusion. C\"- Reject H0. There is not sufficient evidence to conclude that the means for the three treatments are not equal. '1'.\"- Do not reject H0. There is sufficient evidence to conclude that the means for the three treatments are not equal. C.\"- Dq not reject H0. There is not sufcient evidence to conclude that the means for the three treatments are not equal. {93 Reject H0. There is sufficient evidence to conclude that the means for the three treatments are not equal