The following function should return a copy of the input string with all digits removed. However it contains a logic error. What's wrong, and how would you fix it$?$

def remove$\_$digits$($s$)$:

new$\_$s $=""$

for letter in s:

if letter.isdigit$()$:

new$\_$s $=$ new$\_$s $+$ letter

return new$\_$s

Group of answer choices

The code adds characters if they are digits, rather than if they're not digits. The condition should be reversed.

def remove$\_$digits$($s$)$:

new$\_$s $=""$

for letter in s:

if not letter.isdigit$()$:

new$\_$s $=$ new$\_$s $+$ letter

return new$\_$s

new$\_$s should be reassigned to the matching letter each time the loop finds a digit.

def remove$\_$digits$($s$)$:

new$\_$s $=""$

for letter in s:

if letter.isdigit$()$:

new$\_$s $=$ letter

return new$\_$s

The string concatenation for new$\_$s is backwards. It should be

def remove$\_$digits$($s$)$:

new$\_$s $=""$

for letter in s:

if letter.isdigit$()$:

new$\_$s $=$ letter $+$ new$\_$s

return new$\_$s

There should not be a new$\_$s$,$ instead modify s directly.

def remove$\_$digits$($s$)$:

for letter in s:

if letter.isdigit$()$:

s $=$ s $+$ letter

return s