The following function swaps two integers, without requiring a temporary variable: void tricky_swap(int& a, int& b) {
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Question:
The following function swaps two integers, without requiring a temporary variable: void tricky_swap(int& a, int& b)
{
a = a - b;
b = a + b;
a = b - a;
}
However, it fails in one important case, namely when calling tricky_swap(x, x). Explain what should hap pen and what actually happens.
Expert Answer:
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