Question: The following OCTAVE code includes some syntax errors. If there were no syntax errors, what would be the value of x after the execution of

The following OCTAVE code includes some syntax errors. If there were no syntax errors, what would be the value of x after the execution of the code? x = 0; for k 1:80 if (rem (k, 2) == 0) && rem (k, 3) == 0 X = x + 3; end x = x + 1; end

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