Question: The following program does not type check. Which explanation is correct? f :: a -> a > a fx y = if x > y

The following program does not type check. Which explanation is correct? f :: a -> a > a fx y = if x > y then x else y You cannot use if-branching in Haskell. You cannot compare values for inequality in Haskell. You cannot compare values of type a for inequality when they are not a member of Ord class. Testing for in equality is impossible without knowing the precise type. None of the above

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