The function 1s_odd () takes 1 parameters type of double returns a 1 if the number is odd and if the number is even. The function print_is_odd () prints out "Number is ODD" if the input parameter is 1, and "Number is EVEN" if the input parameter is 0. However, the code produces the wrong output when executed as shown in the figure below. Rewrite the single line of code that will fix this bug. mainc 1 #include 2 3 int is odd (int n); 4 void print_is_odd(int flag); 5. int main() 6 7 int number = 89; 8 print_is_odd(is_odd(number)); 9 10 return; 11 } 12 13. int is_odd(int n){ 14 - if (n/2 == 0){ 15 return 1; 16 - } else { 17 return 0; 18 } 19} 20 21. void print_is_odd(int flag){ 22 - if(flag == 1){ printf("Number is ODD"); 24 - } else { 25 printf("Number is EVEN"); 26 } 27 } 23 input Number is EVEN ... Program finished with exit code o Press ENTER to exit console