The function $f(x)=x^4-18x^2+12$ has a derivative of $f^{\text{'}}(x)=4x^3-36x=4x(x^2-9).$

Determine the $x-$values that should be evaluated in $f(x)$ to find the extreme values of the function on the interval $-1,6$ according to the extreme value function. Select all that apply. This question does not require you to solve for the extreme values.

$x=2$

$x=5$

$x=-1$

$x=0$

$x=3$

$x=-3$

$x=4$

$x=1$

$x=-2$

$x=6$