Question: The function f(x) = 4t^3 - 57t^2 + 210t + 6 is the vertical location of an object where f is in ft and t

The function f(x) = 4t^3 - 57t^2 + 210t + 6 is the vertical location of an object where f is in ft and t is in sec.

  • Solve for an expression for the object's velocity.
  • Solve for an expression for the object's acceleration.
  • Solve for an expression for the object's speed.
  • Solve for its displacement during the beginning five secs.
  • Solve for its average velocity during the beginning five secs.
  • Solve for the instantaneous velocity where time is 2.
  • Solve for the acceleration of the object where time is 2.
  • For which values will the object change direction?
  • Solve for the acceleration each time the object changes direction.
  • Solve for the speed of the object when time is 3 secs.
  • Solve for the total distance the object travels over the beginning ten secs.

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