The function $p(t)=\frac{2000t}{4t+75}$ gives the population $pof$ deer $inan$ area after $t$ months.

$a{p}^{\text{'}}(11),p^{\text{'}}(55),$ and $p^{\text{'}}(110).$

$b{p}^{\text{'}\text{'}}(11),p^{\text{'}\text{'}}(55),$ and $p^{\text{'}\text{'}}(110).$

$c{p}^{\text{'}}(11)=$

$(Typean$ intege

ree decimal places $as$ needed.$)$

deer.

months.

dee$\frac{r}{m}$onth ${?}^{(}()2).$

dee$\frac{r}{m}$onth.