The function x) 2 2:23 6::2 210:: l 7 is increasing on the interval (oo,A) U (B, 00) and decreasing on the interval (11,3). A : and B : f is concave up on (C, 00) and concave down on (00, C]. C : The function :r 4+2:2 9(3) = is concave up on (A, B) U (C, 00) and concave down on (oo,A) U (B, C]. A = . B = , and C 2 Find the critical point and the interval on which the given function is increasing or decreasing, and apply.r the First Derivative Test to the critical point. Let ftZ) = 91% Critical Point: x: ls f at a local maximum or a local minumum at the critical point? ? v "o the left ofthe critical point. f is ? v because f' is ? v . "o the right of the critical point, fis ? v because f'is ? v _ Find all points ofinection of F(a:] : :I:1Ilia + 4. t . } For this question, write the inection point as a point on the graph. la a point of the form (a, u\" Find the critical point and the local extreme value ofthe function x] : 3::2 4m + 4 on (00, 00). The critical point is :I: = _ The local extreme value is x) : Find the local extreme values of z) = 32:3 9:1':2 1353 + 7. The local minimum value is and the local maximum value is Note: Local minimum value refers to the value of the function at the local minimum. Consider the function f{:l) = (si_r12:1:)4'IFS on {17/12,71'/3). "he critical points of f are