Question: The function y= (X 4)2(x 7)(x+ 3)3 is negative on the intervals 0 (3, 4) and (4, 7) 0 (negative infinity, -3) and (7, infinity)

The function y= (X 4)2(x 7)(x+ 3)3 is negative on the intervals 0 (3, 4) and (4, 7) 0 (negative infinity, -3) and

and (4, 7) Given the function y= 2x3 3x2 5x+ 1, which

The function y= (X 4)2(x 7)(x+ 3)3 is negative on the intervals 0 (3, 4) and (4, 7) 0 (negative infinity, -3) and (7, infinity) O (3, 4) and (7, infinity) 0 (negative infinity, 3) and (4, 7) Given the function y= 2x3 3x2 5x+ 1, which finite differences will be equal (or constant)? 0 sixth differences 0 first differences 0 third differences 0 second differences

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