Question: The general form of a conic section is given by Equation 1 . 1 0 as Ax 2 + Bxy + Cy 2 + Dx

The general form of a conic section is given by Equation 1.10as
Ax2+Bxy+Cy2+Dx+Ey+F=0Ax2+Bxy+Cy2+Dx+Ey+F=0
In this case, A=4, B=0, and C=1. Since AC, the conic section is not a circle or line.
Calculate the discriminant.
B24AC=(0)2(4)(4)(-1)=16

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