Question: The general solution to the second - order differential equation d 2 ydt 2 4 dydt + 1 0 y = 0 d 2 ydt

The general solution to the second-order differential equation d2ydt24dydt+10y=0d2ydt24dydt+10y=0 is in the form y(x)=ex(c1cosx+c2sinx).y(x)=ex(c1cosx+c2sinx). Find the values of and ,, where >0.

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