The generator polynomial of a cyclic code is given as g(x) = 1+x+x* i. Draw the...

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The generator polynomial of a cyclic code is given as g(x) = 1+x+x* i. Draw the diagram of feedback shift register encoder for the Linear Cyclic code (3 Marks) Illustrate the encoding procedure with the message vector [b b b b] by using the states of the register(the right most bit is the earliest bit) and obtain the final codeword. (7 Marks) iii. Verify the codeword obtained in part c polynomial division method (3 Marks) iv. Derive a syndrome computation circuit for this code. (2 Marks) ii. Digital Communication (ELEC 20004.1)-Summer-2021-CW (Assignment 2)-All-QP Let r=[c c cccc c ] be a received vector. Compute the syndrome of r(t). Display the contents of the syndrome register after each digit of r has been shifted into the syndrome computation circuit. (6 Marks) Compare the syndrome computation performed part v by performing polynomial division method. (4 Marks) V. vi. The generator polynomial of a cyclic code is given as g(x) = 1+x+x* i. Draw the diagram of feedback shift register encoder for the Linear Cyclic code (3 Marks) Illustrate the encoding procedure with the message vector [b b b b] by using the states of the register(the right most bit is the earliest bit) and obtain the final codeword. (7 Marks) iii. Verify the codeword obtained in part c polynomial division method (3 Marks) iv. Derive a syndrome computation circuit for this code. (2 Marks) ii. Digital Communication (ELEC 20004.1)-Summer-2021-CW (Assignment 2)-All-QP Let r=[c c cccc c ] be a received vector. Compute the syndrome of r(t). Display the contents of the syndrome register after each digit of r has been shifted into the syndrome computation circuit. (6 Marks) Compare the syndrome computation performed part v by performing polynomial division method. (4 Marks) V. vi.

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To address the questions regarding the cyclic code and its encoding and decoding procedures lets go through each part step by step i Feedback Shift Register Encoder A Feedback Shift Register FSR encod... View the full answer