The graph of a function f is shown. yA Does f satisfy the hypotheses of the Mean Value Theorem on the interval [0, 5]? O Yes, because f is continuous on the closed interval [0, 5] and differentiable on the open interval (0, 5). O Yes, because f is continuous on the open interval (0, 5) and differentiable on the closed interval [0, 5]. Yes, because f has a maximum on the closed interval [0, 5]. O No, because f is not continuous on the open interval (0, 5). O No, because f does not have a minimum on the closed interval [0, 5]. O No, because f is not differentiable on the open interval (0, 5). X If so, find a value c that satisfies the conclusion of the Mean Value Theorem on that interval. (If an answer does not exist, enter DNE.) C =The graph of a function f is shown. VA Does f satisfy the hypotheses of the Mean Value Theorem on the interval [0, 5]? O Yes, because f is continuous on the closed interval [0, 5] and differentiable on the open interval (0, 5). O Yes, because f is continuous on the open interval (0, 5) and differentiable on the closed interval [0, 5]. O Yes, because f is increasing on closed interval [0, 5]. O No, because f is not differentiable on the open interval (0, 5). O No, because f is not continuous on the open interval (0, 5). O No, because f does not have a minimum nor a maximum on the closed interval [0, 5]. If so, find a value c that satisfies the conclusion of the Mean Value Theorem on that interval. (If an answer does not exist, enter DNE.) C=The graph of a function f is shown. Does f satisfy the hypotheses of the Mean Value Theorem on the interval [0, 5]? O Yes, because f is continuous on the open interval (0, 5) and differentiable on the closed interval [0, 5]. O Yes, because f has a maximum on the closed interval [0, 5]. O Yes, because f is continuous on the closed interval [0, 5] and differentiable on the open interval (0, 5). O No, because f has two minimum values on the closed interval [0, 5]. O No, because f is not differentiable on the open interval (0, 5). O No, because f is not continuous on the open interval (0, 5). If so, find a value c that satisfies the conclusion of the Mean Value Theorem on that interval. (If an answer does not exist, enter DNE.) C =Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem. (Enter your answers as a comma-separated list.) f(x) = x3 - 4x2 - 16x + 6, [-4, 4] C 4Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem. (Enter your answers as a comma-separated list.) f (x) = x+ 1 X 4 C =Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = x5 - 3x + 7, [-2, 2] O Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem. Yes, f is continuous on [-2, 2] and differentiable on (-2, 2) since polynomials are continuous and differentiable on R. O No, f is not continuous on [-2, 2]. O No, f is continuous on [-2, 2] but not differentiable on (-2, 2). O There is not enough information to verify if this function satisfies the Mean Value Theorem. If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list. If it does not satisfy the hypotheses, enter DNE). C=Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f ( x ) = 1, x [1, 5] O Yes, it does not matter if fis continuous or differentiable, every function satisfies the Mean Value Theorem. Yes, f is continuous on [1, 5] and differentiable on (1, 5). O No, f is not continuous on [1, 5]. O No, f is continuous on [1, 5] but not differentiable on (1, 5). O There is not enough information to verify if this function satisfies the Mean Value Theorem. X If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list. If it does not satisfy the hypotheses, enter DNE). C = 5 X