The graph shown is {{x) = 2x2. What is the integral that denes the area under this line between 3: = -1 and x = 1? The graph shown is x) = x + 3. What is the integral that denes the area under this line between x = 1 and x = 5? \fWhat is f(x) given the integral function f(x) = u-1/2d u? I Of(x) =x-1/2 Of(x) = -21/2 Of(x) = -2-1/2 Of(x) = 2x-3/2 3The graph shown is f(x) = x2. If g(x) = f(t )d t, find g '(3). LY 8- 2 4 -2 N -2 Created with a trial version of Advant O g '(3) = 9 O g '(3) = 5 O g '(3) = 7.5 O g '(3) = 11.5\fWhat is f(x) given the integral function f(x) = " vudu? O f( x ) = - O f(x) = Va Of(x) =. VI 2 Of(x) = 1 IThe graph shown is f(x) = sin x + 1. What is the integral that defines the area below this line between x = 0 and x = T ? 114 O g(x) = " (sint -1)d t O g(x) = for (sint - 1)dt O g(x) = [* (sint + 1) dt O g(x) = = (sint + 1)dt