Question: The hitn was the function modifies the original list and does not return anything. def crossout(table,row,col): Modifies the table to remove the given row

The hitn was the function modifies the original list and does not return anything.

def crossout(table,row,col): """ Modifies the table to remove the given row and column. Examples: If a = [[1,3,5],[6,2,7],[5,8,4]], crossout(a,1,2) changes a to [[1,3],[5,8]] If a = [[1,3,5],[6,2,7],[5,8,4]], crossout(a,0,0) changes a to [[2,7],[8,4]] If a = [[1,3],[6,2]], crossout(a,0,0) changes a to [[2]] If a = [[6]], crossout(a,0,0) changes a to [] Parameter table: the nested list to modify Precondition: table is a table of numbers. In other words, (1) table is a nested 2D list in row-major order, (2) each row contains only numbers, and (3) each row is the same length. Parameter row: the row to remove Precondition: row is an index (int) for a row of table Parameter col: the colummn to remove Precondition: col is an index (int) for a column of table """ pass

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