The ice cream cone shown below can be approximated as follows: scoop on top = uniform...

 

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The ice cream cone shown below can be approximated as follows: scoop on top = uniform solid sphere (M = 0.02 kg and R = 0.03 m) waffle cone base cylinder (M2 = 0.034 kg and R2 = 0.01 m), which is uniform and solid also (it's filled with ice cream!) M ice cream cone R R M If this entire ice cream cone were to be rotated about the axis shown, Rotational Inertia: a.) What would the the rotational inertia (I) of: scoop on top: I = 0.0000072 kg-m cone base: I2 = 0.0000017 kg.m the whole ice cream cone: Itot = 0.0000089 kg.m b.) Your friend Bob proposes that you can do this calculation more easily. He condenses the entire ice cream cone into a point mass located at the its center of mass, then uses the point mass formula (I=mr). What would be the distance "r" that he would use, and the rotational inertia that would result from his calculation? r = 0.0174 I 0.0128 x m x kg-m Is Bob's method correct? no; you need to use the object's exact shape in your "I" calculations V c.) You hold this ice cream cone at rest in your hand and then decide to give it a 1.5 second lick, as follows: . With your hand you apply a force of size F2-5.75-103 N to the outside of the cone . With your tongue, you exert a force of size F1-3-10-3 N to the outer edge of the scoop, such as to rotate it in the opposite direction as your hand (this loads ice cream onto your tongue!) . Both forces are applied tangentially to the rotation. For the whole ice cream cone, please find the following quantities. (Note only sizes are requested; answers should be +.) size of the net torque it experiences: 0.0000325 size of its angular acceleration: 4.214 N-m rad/s angle the cone will rotate through during your lick: 0.264 17 X radians X degrees The ice cream cone shown below can be approximated as follows: scoop on top = uniform solid sphere (M = 0.02 kg and R = 0.03 m) waffle cone base cylinder (M2 = 0.034 kg and R2 = 0.01 m), which is uniform and solid also (it's filled with ice cream!) M ice cream cone R R M If this entire ice cream cone were to be rotated about the axis shown, Rotational Inertia: a.) What would the the rotational inertia (I) of: scoop on top: I = 0.0000072 kg-m cone base: I2 = 0.0000017 kg.m the whole ice cream cone: Itot = 0.0000089 kg.m b.) Your friend Bob proposes that you can do this calculation more easily. He condenses the entire ice cream cone into a point mass located at the its center of mass, then uses the point mass formula (I=mr). What would be the distance "r" that he would use, and the rotational inertia that would result from his calculation? r = 0.0174 I 0.0128 x m x kg-m Is Bob's method correct? no; you need to use the object's exact shape in your "I" calculations V c.) You hold this ice cream cone at rest in your hand and then decide to give it a 1.5 second lick, as follows: . With your hand you apply a force of size F2-5.75-103 N to the outside of the cone . With your tongue, you exert a force of size F1-3-10-3 N to the outer edge of the scoop, such as to rotate it in the opposite direction as your hand (this loads ice cream onto your tongue!) . Both forces are applied tangentially to the rotation. For the whole ice cream cone, please find the following quantities. (Note only sizes are requested; answers should be +.) size of the net torque it experiences: 0.0000325 size of its angular acceleration: 4.214 N-m rad/s angle the cone will rotate through during your lick: 0.264 17 X radians X degrees