The indicated function ${}_1(x)is$ a solution $of$ the given differential equation.

$6y^{\text{'}\text{'}}+y^{\text{'}}-y=0$;$,y_1=e^{\frac{x}{3}}$

Use reduction $of$ order $or$ the given formula, $as$ instructed.

$y_2=y_1(x)\frac{e^{-{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}P(x)dx}}{y_1^2(x)}dx$

Find the integrating factor:

$e^{-{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}P(x)dx}=$

Find a second solution ${}_2().$

$y_2=$