The indicated function $y_1(x)$ is a solution of the following differential equation.

$y^{\text{'}\text{'}}-12y^{\text{'}}+36y=0$;$,y_1=e^{6x}$

Use reduction of order, or the formula

$y_2=y_1(x){\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{e^{-{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}P(x)dx}}{y_1^2(x)}dx$

as instructed, to find a second solution $y_2(x).$

$y_2=$