The integral 9 To x (1 + x) is improper for two reasons: The interval [0,...

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The integral 9 To √x (1 + x) is improper for two reasons: The interval [0, ∞o) is infinite and the integrand has an infinite discontinuity at 0. Evaluate it by expressing it as a sum of improper integrals of Type 2 and Type 1 as follows. 9 So® √x (1 + x) dx 9 dx = ° = S₁² √x (² + x) dx + 1₁²^ √x (₁² + x) dx The integral 9 To √x (1 + x) is improper for two reasons: The interval [0, ∞o) is infinite and the integrand has an infinite discontinuity at 0. Evaluate it by expressing it as a sum of improper integrals of Type 2 and Type 1 as follows. 9 So® √x (1 + x) dx 9 dx = ° = S₁² √x (² + x) dx + 1₁²^ √x (₁² + x) dx