Question: The internal energy of a system changes because the system gains 1 6 0 J of heat and performs 3 4 1 J of work.
The internal energy of a system changes because the system gains J of heat and performs J of work. In returning to its initial state, the system loses J of heat. During this return process, what work is involved? If the work is done by the system, then give the work involved as a positive number. If the work is done on the system, then give the work involved as a negative number.
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