The inverse of input$\_$width is $1/$ input$\_$width. The following program intends to read a floating$-$point value from input, compute the inverse of the value, and output the inverse, but the code contains an error. Find and fix the error.

Ex: If the input is $0\mathrm{.}590,$ then the output is:

The inverse of width $=\frac{1}{0\mathrm{.}590}=1\mathrm{.}695$

# Modify the following code

input$\_$width $=$ int $($input $())$

width$\_$inverse $=\frac{1}{?}$ input$\_$width

print$(f^{\text{'}}$ The inverse of width input$\_$width: $\{$:$3f\}=\{widt{h}_i$nverse:$\mathrm{.}3f{\}}^{\text{'}}$