The Leslie matrix in the previous problem was 0.2 0.3 0.5 0.9 0 0 0 0.7...

 

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The Leslie matrix in the previous problem was 0.2 0.3 0.5 0.9 0 0 0 0.7 0.3 Use Wolfram Alpha to compute the dominant eigenvalue. Use trial and error to answer this question. If you can change the survival rate for adults (life stage 3), then what would be the smallest survival rate that makes this population stable or increase in the long-term? Use trial and error to find the smallest number that when you change that entry in the matrix, the population does not decay in the long-term Give your answer up to one digit past the decimal point. eg. 0 or 0.1 or 0.2 or 0.3 or 0.4 or 0.5 or 0.6 or 0.7 or 08 or 1 The Leslie matrix in the previous problem was 0.2 0.3 0.5 0.9 0 0 0 0.7 0.3 Use Wolfram Alpha to compute the dominant eigenvalue. Use trial and error to answer this question. If you can change the survival rate for adults (life stage 3), then what would be the smallest survival rate that makes this population stable or increase in the long-term? Use trial and error to find the smallest number that when you change that entry in the matrix, the population does not decay in the long-term Give your answer up to one digit past the decimal point. eg. 0 or 0.1 or 0.2 or 0.3 or 0.4 or 0.5 or 0.6 or 0.7 or 08 or 1

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To find the dominant eigenvalue by trial and error you can iteratively adjust the survival rate for ... View the full answer