The logarithmic form of the equation $e^x=3$ can be expressed as $x=ln(3).$

The logarithmic form of the equation $e^9=y$ can be expressed as $y=ln(9).$

$\underset{x}{lim}(1\mathrm{.}008{)}^x=1$

$\underset{x{7}^{-}}{lim}{e}^{\frac{3}{7-x}}=$

$\underset{x(\frac{}{2}{)}^{-}}{lim}{e}^{tan(x)}=0$

If $f$ is continuous and ${\displaystyle \underset{0}{\overset{8}{}}}f(x)dx=9,$ then ${\displaystyle \underset{0}{\overset{2}{}}}{x}^{2}f(x^3)dx=27.$