The logic of this flowchart is consistent with only one of the three Java code fragments that follow

A flowchart, oriented from top to bottom. All right branches are labeled "true" and left branches are labeled "false". The primary arrow at the top leads to a rectangle with contents "ans$=0",$ and arrow down from there leads to a diamond with label $"$W$?".$ A right branch from that leads to another diamond labeled $"$X$?"$ that itself has two branches. The right branch for $"$X$?"$ leads to a rectangle labeled "ans$+=1"$ and the left branch continues to merge with the right branch below. That merged branch leads to a rectangle labeled "ans$+=2"$ before merging near the bottom of the diagram. Returning to the diamond labeled $"$W$?",$ its left branch leads to another diamond labeled $"$Y$?".$ That $"$Y$?"$ diamond has two branches, with the right one leading to another diamond labeled $"$Z$?".$ That diamond has a right branch leading to a rectangle labeled "ans$+=4"$ and a left branch that continues to merge with the right below. The left branch of the diamond label $"$Y$?"$ leads to a rectangle labeled "ans$+=8"$ which then merges with the aforementioned branch, and that reaches the final merge at bottom.

Question $7$ options:

ans $=0$;

if $($W$)\{$

if $($X$)$

ans $+=1$;

ans $+=2$;

$\}$ else if $($Y$)\{$

if $($Z$)$

ans $+=4$;

$\}$ else

ans $+=8$;

ans $=0$;

if $($W$)\{$

if $($X$)$

ans $+=1$;

else

ans $+=2$;

$\}$ else if $($Y$)\{$

if $($Z$)$

ans $+=4$;

$\}$ else

ans $+=8$;

ans $=0$;

if $($W$)\{$

if $($X$)$

ans $+=1$;

ans $+=2$;

$\}$ else if $($Y && Z$)\{$

ans $+=4$;

$\}$ else

ans $+=8$;