The MAD for the forecast developed using a weighted$2-$year moving average with weights of $0\mathrm{.}35$ and $0\mathrm{.}65=$

$$

$150$ miles $($round your response to one decimal$$ place$).($Hint: You will have only $3$ years of matched$$ data.$)$

Part $6$

$$d$)$ Using exponential smoothing with alpha $=0\mathrm{.}20$ and the forecast for year $1$ being $3$ comma $100,$ the forecast for year $6=$