Question: The matrix -3 0 1 A = 0 -2 0 -1 0 -1 has a single real eigenvalue x = -2 with algebraic multiplicity three

The matrix

-3 0 1

A = 0 -2 0

-1 0 -1

has a single real eigenvalue x = -2 with algebraic multiplicity three

(a)Find a basis for the associated eigenspace

Basis = {___________}

(b) is the matrix A defective?

A. A is not defective because the eigenvalue has algebraic multiplicity three

B. A is not defective because the eigenvectors are linearly independent

C. A is defective because it has only one eigenvalue

D.A is defectivve because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicity

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