Question: The matrix -3 0 1 A = 0 -2 0 -1 0 -1 has a single real eigenvalue x = -2 with algebraic multiplicity three
The matrix
-3 0 1
A = 0 -2 0
-1 0 -1
has a single real eigenvalue x = -2 with algebraic multiplicity three
(a)Find a basis for the associated eigenspace
Basis = {___________}
(b) is the matrix A defective?
A. A is not defective because the eigenvalue has algebraic multiplicity three
B. A is not defective because the eigenvectors are linearly independent
C. A is defective because it has only one eigenvalue
D.A is defectivve because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicity
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