The maximum $($peak$)$ value of a voltage given by asin$(t)+$bcos$(t)$ can be determined using the formul $A=\sqrt[\phantom{2}]{a^2+b^2}.$ Assume a voltage is given by:

$v(t)=4sin(t)+cos(t),t>0$

i$)$ Determine the peak voltage, $A.$

Note: Enter exact value, say ${15}^{{?}^{{?}^{?}}}(\frac{1}{2}).$

$A=$

$(2$ Mark$)$

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