The molarity of a solution is 0.15 M in NaI (aq) at 298.15 K. A large excess
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The molarity of a solution is 0.15 M in NaI (aq) at 298.15 K. A large excess of HgI2 (s) to the solution. What is the solubility (in grams) of HgI2 (s) at saturation?
HgI2 (s)<------->Hg2+ (aq) + 2I- (aq) Ksp= 2.7 × 10^-29
HgI2 (s) + 2I- <------> [HgI4]2- (aq) Kf= 0.75 M
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