The NIH is creating a test for the Zika virus. The incidence of a Zika is low, 0.11 (or 11 %) in the general population. In symbols, this says "P(D) = 0.11". This test sometimes misses detecting the disease. That is, sometimes a person with the disease will get a negative test. This probability of a false negative is 0.03 (or as a percent, 3 %) . In symbols, this says that "P(Negative | D) = 0.03". Similarly, someone who does not have Zika, will sometimes get a positive reading. The probability of this false positive is 0.2 percent. In symbols, "P(Positive | No D) = 0.2." Fill in the tree diagram. Answer in decimals rounded to at least 4 places. Arrows for Tree Diagram Disease Presence Arrows for Tree Diagram Arrows for Tree Diagram Conditional Probabilities Joint Probabilities P(positive|D) P(D and positive) False negative P(D) P(negative|D) P(D and negative) False Positive P(no D) P(positive|no D) P(no D and positive) P(negative|no D) P(no D and negative) Given that a person gets a positive test, calculate the probabilty that the person has Zika