The null and alternative hypothesis would be:

$H_0$:$p0\mathrm{.}725H_0$:$2\mathrm{.}9,H_0$:$=2\mathrm{.}9,H_0$:$p0\mathrm{.}725H_0$:$p=0\mathrm{.}725H_0$:$2\mathrm{.}9$

$H_1$:$p>0\mathrm{.}725H_1$::$2\mathrm{.}9,H_1$:$p<mn\; id="EditorElement\_412037">0</mn><mn\; id="EditorElement\_412038">.</mn><mn\; id="EditorElement\_412039">7</mn><mn\; id="EditorElement\_412040">2</mn><mn\; id="EditorElement\_412041">5</mn><msub\; id="EditorElement\_412050"><mrow><mi\; id="EditorElement\_412043">H</mi></mrow><mrow\; id="EditorElement\_412049"><mn\; id="EditorElement\_412046">1</mn></mrow></msub>$:$p0\mathrm{.}725H_1$:$>2\mathrm{.}9$

The test is:

two$-$tailed right$-$tailed left$-$tailed

Based on a sample of $45$ people, the sample mean GPA was $2\mathrm{.}92$ with a standard deviation of $0\mathrm{.}05$

The $p-$value is:

$($to $2$ decimals$)$

Based on this we:

Fail to reject the null hypothesis

Reject the null hypothesis