Question: The objective function for this optimization problem is: MAX: X1 + X2 + X3 + X4 + X5 + X6 + X7 Where... X1 =

The objective function for this optimization problem is: MAX: X1 + X2 + X3 + X4 + X5 + X6 + X7 Where... X1 = the number of individuals hired to Schedule #1 (do not work on Sunday and Monday) X2 = the number of individuals hired to Schedule #2 (do not work on Monday and Tuesday ) X3 = the number of individuals hired to Schedule #3 (do not work on Tuesday and Wednesday) X4 = the number of individuals hired to Schedule #4 (do not work on Wednesday and Thursday) X5 = the number of individuals hired to Schedule #5 (do not work on Thursday and Friday) X6 = the number of individuals hired to Schedule #6 (do not work on Friday and Saturday) X7 = the number of individuals hired to Schedule #7 (do not work on Saturday and Sunday)

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