The other blank says alternative or null

E Homework: ... Question 22, 8.1.33 HW Score: 40.02%, 68.43 of 171 points Save tid O Points: 0 of 3 In a clinical trial of a drug intended to help people stop smoking, 125 subjects were treated with the drug for 13 weeks, and 12 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value of p, the power of the test is 0.95. Interpret this value of the power of the test. The power of 0 95 shows that there is a % chance of rejecting the hypothesis of p = when the true proportion is actually That is, if the proportion of users who experience abdominal pain is actually , then there is a % chance of supporting the claim that the proportion of users who experience abdominal pain is than 0.08 (Type integers or d und.) greater less