The output of the Python code will be $[2,3,[4,5]][88,3,[4,5]].$ Here$$s why:

The line l$2=$l$.$copy$()$ creates a shallow copy of l and assigns it to l$2.$ This means that l$2$ is a new list with the same elements as l$.$ However, because this is a shallow copy, the sublists of l $($like $[4,5])$ are not copied but are referenced.

When l$2[0]=88$ is executed, it changes the first element of l$2$ to $88,$ but l remains unchanged because l$2$ is a separate list.

So$,$ the correct answer would be:

b$.[2,3,[4,5]][88,3,[4,5]]$