Question: The PC station is 1 2 + 2 5 . 3 2 ft . , the degree of curvature is 1 0 degrees, and the

The PC station is 12+25.32 ft., the degree of curvature is 10 degrees, and the length of curve is 638.90 ft.. What is the deflection angle and subchord from the PC to station 16+00.00?

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