Question: The permanent action ( G ) ( including self - weight ) applied to a beam is 1 5 kN / m and the imposed

The permanent action (G)(including self-weight) applied to a beam is 15kN/m and the imposed load (Q) is 12kN/m. The loads to use for a strength limit state analysis, and to calculate the short term deflection of a beam in an office respectively are: (a) None of the other answers is correct{b) w*=36.9 kN/m; Ws =23.4 kN/m (c) w*=36 kN/m; Ws =19.8 kN/m(d) w*=36 kN/m; Ws =19.8 kN/m(e) w*=36 kN/m; Ws =23..4 kN/m
a) Calculate from first principles (ERSB) the value of the design pure axial compression
capacity o(in kN ).
b) Calculate the depth of the plastic centroid, dpc , from the indicated compression face and
explain the significance of this point in terms of the behaviour of the column (ie if a load is
applied at this point, what is the effect on the column).
c) Show that the design bending capacity under pure moment, Muo, is 1345 kNm using
the ERSB. To do this you will need to calculate the effective depth, d , and the neutral axis
depth parameter, ku , to check ductility. Hint: assume that As1 is in compression and As2
and As3 are in tension.
d) Calculate from first principles (ERSB) the design capacities at the 'balanced' condition, Mub
and Nub.
e) Approximating this column's design interaction diagram as a straight line between pure
compression Nuo and the 'balanced' condition b and b, and another straight line
between pure moment Muo and the 'balanced' condition, is this proposed column cross-
section adequate to carry the design actions N** and M**? Verify this by plotting these
various values on the following page.
The permanent action ( G ) ( including self -

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Civil Engineering Questions!