Question: The position function of an object is given by s + ts = 2t, where the position, s, is a function of time, t, for

 The position function of an object is given by s³ +
t²s = 2t, where the position, s, is a function of time,

The position function of an object is given by s³ + t²s = 2t, where the position, s, is a function of time, t, for t ? If ds/dt=2-2st/3s^2+t^2 determine why the acceleration is not defined at t = 0. 2-2st = 0 for t = 0 and s = 02-2st=0 for t = 0 and s = 1(3s² +1²)² = 0 for t = 0 and s = 0(3s² + 2)2 = 0 for t = 0 and s = 1

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