Question: The program show below takes a number of command line arguments, prints all the arguments out to screen, and converts the argument argv[1] to integer

 The program show below takes a number of command line arguments,

The program show below takes a number of command line arguments, prints all the arguments out to screen, and converts the argument argv[1] to integer and then prints it to screen. Recall, argv[O] is the executable name, argv[1] is the first parameter, argv[2] is the second parameter, etc. You can try this program out yourself to see how to pass command line arguments to your program. #include #include int main(int arge, char *argv[]) { if (argc #include int main(int arge, char *argv[]) { if (argc

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